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<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'>PRACTICAL PROBLEMS<o:p><=
/o:p></span></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><o:p>&nbsp;</o:p></span>=
</p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>An <span class=3DSpellE>eter=
</span>
pump (EP) has one or two rails to drive <span class=3DSpellE>eter</span>-io=
ns.
They are high voltage electrodes. Working in air they must be covered by a
thick insulator material. Such material must be slightly conductive. If not,
equipotential surface move and the dielectric can burn down. In air, that
surface of highest voltage is the electrode&#8217;s surface. The insulator&=
#8217;s
external surface is in direct contact with the air. So it is the null volta=
ge
equipotential surface. Inside the insulator material there is a
voltage-gradient. As the high voltage is a little more than the ionizing
voltage, the <span class=3DSpellE>eter</span>-ionizing surface is inside the
insulator. Then eterons disappear at that surface. So the <span class=3DSpe=
llE>eter</span>
flow must cross the insulator from its external surface. In other words, it=
 is
unavoidable an <span class=3DSpellE>eter</span> current through the insulat=
or. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>In the case of a linear EP u=
sed as
NID propulsion unit, the prow is an <span class=3DSpellE>eter</span>-absorb=
ing
end. First it absorbs inside the insulator. The <span class=3DSpellE>eter</=
span>-hole
moves an <span class=3DSpellE>eter</span> current around so from the electr=
ode as
from the frontal part. At the stern it is the <span class=3DSpellE>eter</sp=
an>-emitting
end. It also generates an <span class=3DSpellE>eter</span> flow but emittin=
g as a
source, also through the insulator. Every <span class=3DSpellE>eter</span> =
flow
with matter inside, that matter generates introns of a speed oriented again=
st
the flow. Once the introns are in balance with the flow, at the prow the
frontal part of the EP (the insulator&#8217;s frontal surface) have atoms t=
hat
absorb <span class=3DSpellE>eter</span> with theirs introns. But those intr=
ons do
not push the atoms ahead because at the back <span class=3DSpellE>eter</spa=
n> is
swallowed by the EP. Introns have no loaning surface to push atoms because
instead of being supported at the back they lose <span class=3DSpellE>eter<=
/span>
in the EP. By this way the insulator is a corridor for <span class=3DSpellE=
>eter</span>;
there are no forces between such insulator and the electrode. Now, if the E=
P is
switched off, introns suddenly have support at the back; then if the insula=
tor
is not strongly stuck to the electrode it flies ahead like a projectile. EP
must be inactivated slowly to diminish the intron&#8217;s force, letting th=
em
to accelerate ahead and slowly the whole EP. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>When the EP is working as NI=
D, at
both ends the insulator is in balance with introns. At the back it emits <s=
pan
class=3DSpellE>eter</span>, also through the insulator whose introns
&#8220;pump&#8221; <span class=3DSpellE>eter</span> outwards. Eter do not f=
low
towards the electrode; just emitted <span class=3DSpellE>eter</span> pushes=
 the
whole EP ahead. The only way of emitted <span class=3DSpellE>eter</span> is=
 moving
the EP inside the frontal hole. If the EP is switched off introns will seek=
 to
insert insulator&#8217;s atoms inside the electrode. Again, EP&#8217;s
inactivating must be slow. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>At its time, the frontal abs=
orber
(the prow) do not absorb from the frontal part of the electrodes because
introns of the insulator saturate it. In other words, it is easier to absor=
b <span
class=3DSpellE>eter</span> from outside than from the electrode. <o:p></o:p=
></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>The conclusion is the next: =
one,
the EP must be inactivated slowly. Two, the insulator must be strongly stuc=
k to
the electrode and made up of resistant mechanically material.<o:p></o:p></s=
pan></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>The phenomenon described abo=
ve
limits the craft&#8217;s speed to a low value (not more than a few hundreds=
 of
km/h). High space-speeds like <st1:metricconverter ProductID=3D"100000 km/h"
w:st=3D"on">100000 km/h</st1:metricconverter> are impossible because it wou=
ld
imply to accelerate the insulator covers to such inertial speeds. Moreover,=
 the
craft never could reach the speed of light.<span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp;&nbsp; </span><o:p></o:p></spa=
n></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>What happens in vacuum? As v=
acuum
does not conduct electricity the electrode can face directly to vacuum.
Removing the insulator each time the craft reaches vacuum is definitively n=
ot
practical. If not removed, equipotential surface of ionizing voltage will
migrate to the external surface of the insulator. Remember that such insula=
tor
is slightly conductive. Then it works as a naked electrode. Electric resist=
ance
of the insulator does not disturb; there is NO ELECTRIC current inside the =
high
voltage electrodes while NID works. It conducts only <span class=3DSpellE>e=
ter</span>-ions
that ignore electric resistances.<span style=3D'mso-spacerun:yes'>&nbsp; </=
span><o:p></o:p></span></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><o:p>&nbsp;</o:p></span>=
</p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span class=
=3DGramE><span
lang=3DEN-US style=3D'font-size:14.0pt;mso-ansi-language:EN-US'>Problems wi=
th
lifting wheels (LW).</span></span><span lang=3DEN-US style=3D'font-size:14.=
0pt;
mso-ansi-language:EN-US'><o:p></o:p></span></p>

<p class=3DMsoNormal><span lang=3DEN-US style=3D'font-size:14.0pt;mso-ansi-=
language:
EN-US'><o:p>&nbsp;</o:p></span></p>

<p class=3DMsoBodyText style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Observe the diagram &#8220;L=
IFTING
WHEEL&#8221;. As the wheel spins its material enters and exits fast inside =
the <span
class=3DSpellE>eter</span> flow. Being inside, it acquires introns and the =
EP
generates a dense-<span class=3DSpellE>eter</span>-zone between the emittin=
g end
and the wheel&#8217;s ring, above. So that part of the wheel is inside an <=
span
class=3DSpellE>eter</span>-density-gradient. As a consequence, the Absolute=
 Speed
Vector (ASV) undergoes a deviation (remember the intron-turbine). This time=
 it
can be disturbing. Deviation-angle (between the axis and the ASV) depends on
the orientation of the wheel&#8217;s axis. When the angle is 90&deg;
(horizontal ASV), there is no deviation and even it doubles the lifting for=
ce
(never diminishing). If the angle is null (vertical ASV) it does not distur=
b at
all. An angle of 45&deg; degrees is the worst one. Then the lifting force is
deviated 22.5&deg; degrees regarding vertical. Maybe for a craft soaring in=
 a
wide land means no problem, but in the case of a crane or in the slow and n=
ice
landing of a craft it is unbearable. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>It is solved building the wh=
eel in
such a way that its axis can be tilted to counteract lateral deviation. We =
jump
over the calculation; less than 22&deg; degrees of tilting for the axis is
enough to achieve a vertical force. It is better to only the EP-supports
keeping the wheel&#8217;s axis always vertical with regard to the craft&#82=
17;s
ground. It avoids an intense gyroscope effect of a heavy spinning wheel. <o=
:p></o:p></span></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><o:p>&nbsp;</o:p></span>=
</p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span class=
=3DGramE><span
lang=3DEN-US style=3D'font-size:14.0pt;mso-ansi-language:EN-US'>Health prot=
ection.</span></span><span
lang=3DEN-US style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><o:p></o:p>=
</span></p>

<p class=3DMsoNormal><span lang=3DEN-US style=3D'font-size:14.0pt;mso-ansi-=
language:
EN-US'><o:p>&nbsp;</o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>When the first H-bomb has be=
en
proved at <st1:place w:st=3D"on">Bikini</st1:place> islands an interesting
phenomenon happened. At <st1:metricconverter ProductID=3D"40 km" w:st=3D"on=
">40 km</st1:metricconverter>
far from the explosion an Iowa-type battleship had serious disturbing of its
electronic equipment due to what they knew at that time as
&#8220;electromagnetic pulse&#8221;. It was a strong pulse of <span
class=3DSpellE>subelectricity</span>, an <span class=3DSpellE>eter</span>-i=
on
current. Steel-shield of <st1:metricconverter ProductID=3D"40 cm" w:st=3D"o=
n">40 cm</st1:metricconverter>
did not stop it. At the meantime a submarine was observing the explosion
through the periscope. It was only <st1:metricconverter ProductID=3D"10 km"
w:st=3D"on">10 km</st1:metricconverter> far from the explosion. It underwen=
t not
any electric disturbing effect. What was the difference? It is trivial: the
water shield, one of <st1:metricconverter ProductID=3D"10 km" w:st=3D"on">1=
0 km</st1:metricconverter>
thick. Calculating the energy of that explosion of 1 megaton, if we use EP =
of
double rail whose <span class=3DSpellE>subelectricity</span>-dispersion is =
much
lower than that of an EP of one rail, a water shield of <st1:metricconverter
ProductID=3D"50 cm" w:st=3D"on">50 cm</st1:metricconverter> is enough for a
generating set of many thousands of KW. Although we don&#8217;t know the
protecting mechanism of water, at <st1:place w:st=3D"on">Bikini</st1:place>
islands it worked. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>What changes will the water
undergo after working as shield, let us say, during one year? Will it become
radioactive or poisonous? What will happen if a human being will drink a gl=
ass
of that water? What will happen if we water a plant with it? Is it enough to
throw it into the sea? Or we must treat it before? Or we must send it to the
sun? <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>We&#8217;ll see&#8230;<o:p><=
/o:p></span></p>

<p class=3DMsoNormal><span lang=3DEN-US style=3D'font-size:14.0pt;mso-ansi-=
language:
EN-US'><o:p>&nbsp;</o:p></span></p>

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