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<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><b style=3D=
'mso-bidi-font-weight:
normal'><span style=3D'font-size:16.0pt'>PROPULSION<o:p></o:p></span></b></=
p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><o:p>&nbsp;=
</o:p></p>

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<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'>FLYING CRAFT<o:p></o:p><=
/span></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><o:p>&nbsp;</o:p></span>=
</p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>In the chapter &#8220;THE ET=
ER
PUMP&#8221; we have seen the principles of the device capable to move <span
class=3DSpellE>eter</span>. The diagram above represents a flat flying craf=
t that
has built-in <span class=3DSpellE>eter</span> pumps (EP). They are linear k=
ind.
In the two previous chapters we have seen the C-shaped kind. The above
represented are linear ones. The difference is the next:<o:p></o:p></span><=
/p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>C kind: it generates an <span
class=3DSpellE>eter</span> flow between the ends of the <span class=3DSpell=
E>eter</span>-moving
rails. The flow is in an empty space, being possible to sit any object insi=
de
the flow. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Linear kind: the same pump is
inside the <span class=3DSpellE>eter</span> flow. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>The craft of the upper diagr=
am
works well in vacuum. The pump (EP) moves <span class=3DSpellE>eter</span> =
from
&#8220;v&#8221; zone to &#8220;d&#8221; zone. To pump <span class=3DSpellE>=
eter</span>
without compressing it implies a very low energy input. High kinetic energy=
 of
nuclear particles is due to the fact of compressing <span class=3DSpellE>et=
er</span>
to a high energy level (introns). Such compressing level is proportional to=
 the
particle&#8217;s mass. An EP uses a totally different way to move eterons
because it does not compress them. It ionizes them. Then <span class=3DSpel=
lE>eter</span>-ions
move to hyperspace, enter into the correspondent parallel space and move in=
 a
medium where inertia is diminished by a factor in the order of many million=
s.
Although the ionizing energy is very high at the ionizing zone (v), such en=
ergy
is returned at the regenerating zone (d). Then an EP moves <span class=3DSp=
ellE>eter</span>
with a very low energy. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>&#8220;<span class=3DGramE>d=
</span>&#8221;
zone pushes the craft towards &#8220;v&#8221; zone. To generate introns a
pushing force is needed. But such force cannot exist at &#8220;v&#8221; zone
because eterons are swallowed, being a partial vacuum zone. Then the craft
moves till to compact the whole eterons at &#8220;v&#8221; zone without
reaching a pressure that passes the barrier-force. In other words, the craft
moves into the partial vacuum where eterons are not touching among them, so
they do not generate a pressure. Just reached the compact condition eterons
begin to touch among them and they need a small pressure-increasing to pass=
 the
barrier-value. Then they attract among them and theirs behavior is governed=
 by
quantum rules, forming introns if the craft seeks to move faster than the s=
peed
allowed by the <span class=3DSpellE>eter</span> flow. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>The EP generates an <span
class=3DSpellE>eter</span> flow whose speed is in order of millions higher =
than
the speed of light. It should be the speed limit for the craft. The real sp=
eed
is much lower because it is determined by the flow&#8217;s intensity. <o:p>=
</o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>This kind of propulsion is,
someway, similar to that of a ship that absorbs the water ahead expelling i=
t at
the stern instead of pushing it asides at the prow. Of course, water does n=
ot
pass to the parallel space and it has a very low speed limit. <o:p></o:p></=
span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>&#8220;<span class=3DGramE>v=
</span>&#8221;
zone avoids intron-generating. So this kind of propulsion &#8220;switches
off&#8221; the inertia. Inputting very little energy it is possible to achi=
eve
speeds like that of light (or more). <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>We call this propulsion as N=
ID. <span
class=3DGramE>(Non Inertial Drive.)</span> With such crafts it is possible =
to
reach planets in minutes (at least in hours). <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Now a new problem appears: t=
he
atmosphere. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>NID does not work inside the
atmosphere at very high speeds. &#8220;<span class=3DGramE>v</span>&#8221; =
zone
tries to swallow not only <span class=3DSpellE>eter</span> but also air. Th=
e EP
cannot move air as to <span class=3DSpellE>eter</span>. Then the air crashes
against the prow of the craft. Inputting much more energy to the EP it will
work like inertial propulsion because air is being accelerated (air&#8217;s
resistance). Then &#8220;d&#8221; zone begins to compress eterons against t=
he
craft&#8217;s stern and generate introns backwards. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Another (big) problem is gra=
vity.
If the craft is loaned on ground gravity cannot accelerate it downwards;
gravitons go away without giving or removing energy. Once lifted and in
free-falling condition, NID works well but gravity makes the growing of int=
rons
(downwards) while the craft is going up. In a planet without atmosphere the=
re
is no problem because in seconds the craft is far from the gravity&#8217;s
influence. Potential energy is due to gravitons interchanging energy with
climbing or falling objects; NID moves up the <span class=3DSpellE>eter</sp=
an>
inside which is the craft like in the case of a graviton turbine. So potent=
ial
energy is also &#8220;switched off&#8221;. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>But in a planet with dense
atmosphere it is not possible to run at super-speeds. Going up slowly the c=
raft
must bear gravity. To reach a height of <st1:metricconverter ProductID=3D"8=
0 km"
w:st=3D"on">80 km</st1:metricconverter> at 300 km/hour it takes 16 minutes.=
 The
craft accumulates a speed of 9.6 km/second&#8230; downwards! Once in vacuum=
 it
uses NID to run in seconds 10000 <span class=3DSpellE>kms</span> far around=
 the
Earth (90 degrees in orbit) where that speed is horizontal and it will not =
fall
down.<o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>While it is soaring by the
described way it must counteract the air&#8217;s friction; although the EP
needs an important energy input, it is much less than the whole potential
energy to lift the craft to <st1:metricconverter ProductID=3D"80 km" w:st=
=3D"on">80
 km</st1:metricconverter> high. Malfunction of the EP before reaching safe
height can make a big crater with the craft&#8217;s name.<span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span><o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Landing is a much bigger pro=
blem.
Seemingly, the first thing to achieve is to eliminate speed with regard to =
the
atmosphere. A NID craft can go around the planet in seconds. The crew feels=
 no
accelerations. If the craft has a high speed regarding the planet, it goes =
to
the geographic latitude and longitude where its speed vector is vertical
upwards. Then it approaches the planet <st1:metricconverter ProductID=3D"10=
00 km"
w:st=3D"on">1000 km</st1:metricconverter> above the atmosphere adjusting NI=
D so
as to counteract exactly its speed, staying still with regard to the planet=
 but
running up fast inside the NID flow. Gravity will diminish its speed by sim=
ple
acceleration. Slowly and precisely NID is adjusted (gradually diminished) f=
or
not to fly away upwards till to reach null inertial speed. Then the craft c=
an
enter the atmosphere without burning down. If it has wings and an aerodynam=
ic
shape it lands like a space shuttle. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Nevertheless, such a shape w=
ould
be ridiculous and anachronistic. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>How to achieve a nice and so=
ft
landing? Using NID to decelerate is not possible because during the descent
gravity is working and reaching land the craft can accumulate a very high s=
peed
and once NID is switched off it crashes violently. It is possible to land
reducing the flying speed to such a value that it is null just reaching gro=
und.
The previous speed-eliminating maneuver can do it. The problem is that a sm=
all
error can result in a dangerous remaining speed. This maneuver demands a ve=
ry
precise NID control, ranging, atmosphere pressure and wind measuring system.
Even in a planet without atmosphere it is unavoidable a small falling speed;
small as space-speed, but dangerous for landing. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>It is necessary to achieve a
support system that counteracts gravity&#8217;s effect. <o:p></o:p></span><=
/p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Here we have to do a digress=
ion.
Comparing an <span class=3DSpellE>eter</span> flow with gravity, they seem =
to be
similar. Both generate introns on the opposed sense to the flow. The differ=
ence
is that an <span class=3DSpellE>eter</span> flow drags every mass inside th=
e flow
without inertia and gravity does not. Only a mass supported out of the flow
generates introns. Eter flows are local phenomena (<span class=3DSpellE>ete=
r</span>
moving inside still <span class=3DSpellE>eter</span> around). Gravitons are
waves; if they find on theirs path a mass, they interact with it, leaving it
behind. Moreover, gravitons follow quantum rules; an <span class=3DSpellE>e=
ter</span>
flow does not. In an <span class=3DSpellE>eter</span> flow with a mass with=
in,
increasing the flow&#8217;s intensity, at the first moment the flow is push=
ing
the mass towards its moving direction. Then it forms introns towards the
opposed sense. When introns equal the flow&#8217;s speed, there are no forc=
es. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>In other words, we put a mas=
s in
the flow of an <span class=3DSpellE>eter</span> pump; a dense <span class=
=3DSpellE>eter</span>
bulk appears between the <span class=3DSpellE>eter</span>-source and the ma=
ss;
inside the bulk there is <span class=3DSpellE>eter</span>-pressure and,
simultaneously, it is a graviton source. Then two forces exist: one against=
 the
mass in the sense of the flow, like trying to drag the mass. As such mass is
supported it is not dragged (if it were dragged the force would not exist).
Two: the mass makes a counter-force because eterons of the <span class=3DSp=
ellE>eter</span>
flow push eterons of the mass over the barrier-force attracting the front of
the <span class=3DSpellE>eter</span> flow; then introns are formed against =
the
flow and the mass is accelerated towards the <span class=3DSpellE>eter</spa=
n>-source.
The mass slows the flow and as it is accelerating, the flow recovers its
original speed with regard to the flow. Of course, when we say
&#8220;speed&#8221; it is ALWAYS with regard to the <span class=3DSpellE>et=
er</span>
in which the mass is immersed. There is NO OTHER speed.<o:p></o:p></span></=
p>

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<o:p></o:p></span></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'>LIFTING WHEEL<o:p></o:p>=
</span></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span lang=
=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><o:p>&nbsp;</o:p></span>=
</p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Observe the diagram &#8220;L=
IFTING
WHEEL&#8221;. Lower part is a view of a cut by AA seen from BB. 12 <span
class=3DSpellE>eter</span> pumps (EP) units are represented. The <span
class=3DSpellE>eter</span> flow (zone z) crosses the wheel in parallel sens=
e (<span
class=3DSpellE><span class=3DGramE>df</span></span>) to its axis. The wheel=
 is very
heavy. Its axis is vertical (F). Going step by step:<o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>1* A vertical <span
class=3DSpellE>eter</span> flow is generated by <span class=3DSpellE>eter</=
span>
pumps downwards. It needs a small energy input.<span
style=3D'mso-spacerun:yes'>&nbsp; </span><o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>2<span class=3DGramE>*=
<span
style=3D'mso-spacerun:yes'>&nbsp; </span>We</span> put a mass inside the fl=
ow
(the spinning wheel&#8217;s mass, its tangential speed). <o:p></o:p></span>=
</p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>3<span class=3DGramE>*=
<span
style=3D'mso-spacerun:yes'>&nbsp; </span>The</span> flow would drag down th=
e mass
without inertia but&#8230; <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>4* &#8230;we support t=
he
mass with a bar prolonged out of the flow (the wheel&#8217;s spokes and axi=
s). <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>5* <span class=3DGramE=
>The</span>
flow should stop suddenly but the coil of the <span class=3DSpellE>eter</sp=
an>
pump has self-inductance and reacts, generating a high <span class=3DSpellE=
>eter</span>-pressure
against the obstacle (the mass). <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>6* <span class=3DGramE=
>An</span>
automatic current regulator maintains the flow with high pressure.<span
style=3D'mso-spacerun:yes'>&nbsp; </span><o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>7* <span class=3DGramE=
>The</span>
flow presses the mass on its own sense. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>8* <span class=3DGramE=
>The</span>
mass is accelerated upwards according to the pressure&#8217;s intensity. <o=
:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>9* Introns are generat=
ed in
the mass, (a speed inside the flow, upwards). <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>10* <span class=3DGram=
E>After</span>
a while that speed equals the flow&#8217;s initial speed and no forces will
exist: the supported mass is in balance with the flow. The mass is still wi=
th
regard to the supporting external world and has a speed upwards with regard=
 to
the <span class=3DSpellE>eter</span> flow. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>11* <span class=3DGram=
E>We</span>
remove the mass in horizontal sense (the wheel is spinning) out of the flow=
.<o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp; </span>12* The mass would fly=
 up
with high speed if released; it can not fly up due to the axis, so it will =
make
a high lifting force against its supporting system. A continuous spinning m=
akes
that each mass part of the wheel enters between the ends of a C-shaped EP, =
gets
strong introns and exits to eliminate those introns as lifting force. Such =
mass
part works like every mass that has a speed. The formula F=3D<span class=3D=
SpellE>m.a</span>
(1) (&#8220;F&#8221; is force, &#8220;m&#8221; is mass and &#8220;a&#8221; =
is
acceleration) governs the stopping of that mass. To stop a moving mass in a
given time-interval at a given distance works by the formula a=3Dv/<span
class=3DGramE>t .</span> &#8220;<span class=3DGramE>v</span>&#8221; is the =
speed,
&#8220;a&#8221; is the deceleration and &#8220;t&#8221; is the time it take=
s to
stop. Replacing in (1) we have F=3D<span class=3DSpellE>m.v</span>/<span
class=3DGramE>t .</span> The higher is the speed and the shorter is the
time-interval, the higher is the force. Moreover, the spinning movement of =
the
wheel is perpendicular to that of the mass, so the distance to cover by the
mass is very short because it is given by the torsion due to the wheel&#821=
7;s
flexibility. A shorter distance means a shorter time-interval. &#8220;<span
class=3DGramE>v</span>&#8221; depends on the EP-coil&#8217;s current, that =
is to
say, the intron-energy of the mass. Then increasing the wheel&#8217;s spinn=
ing
speed, &#8220;t&#8221; decreases and the mass demands higher current in the
coils to reach the same introns. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>An outcome of the phenomenon
described above is a very high lifting force because we seek to stop a big =
and
fast mass in a very small distance and in a short time. We insist with the
concept of relative eteronic speed: it is with regard to the conducting med=
ium.
The EP moves such medium downwards; the mass is moving upwards inside that
medium but NOT with regard to the external environment. Moreover, the wheel=
 has
a different movement with regard to the environment: it is the spinning of =
the
wheel and its movement vector is perpendicular to the movement generated by=
 the
EP.<span style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </span><=
o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>The lifting wheel (LW) can
generate very high lifting forces if it is not forced to lift a heavy objec=
t.
If it is still at a fixed height it needs little energy to sustain, for
example, a big craft. It could be used for propulsion but it has a big
disadvantage besides NID because it needs much energy. However, the LW is an
inertial device because it generates introns, like a helicopter. It can be
useful as flying crane. A Chinook-shaped hull with 2 <span class=3DSpellE>L=
Ws</span>
of 10 ton each, applying an <span class=3DSpellE>eter</span> flow equivalen=
t to <st1:metricconverter
ProductID=3D"30 g" w:st=3D"on">30 g</st1:metricconverter> can lift 600 tons=
 using a
generating set of only 1000 HP. It is the intron-crane (IC). In building
industry it will be very useful.<span style=3D'mso-spacerun:yes'>&nbsp;&nbs=
p;
</span><o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>There is an important concep=
t to
clarify: the potential energy. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Let us observe the IC. If it=
 is
staying at a fixed height it needs null energy&#8230; theoretically. A real=
 one
needs energy due to torsions of the wheels, current in coils, etc. (generat=
ing
heat). It is lost energy, as in every electric device. It is far lower than=
 the
energy input of a helicopter of similar weight with fuel-engine in the same
condition. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Now, if our IC seeks to move=
 up
(specially lifting some payload), it needs energy input, so much as its tot=
al weight
requires (added to the lost energy). From the viewpoint of introns and
gravitons, the IC moves up and gravitons leave it upwards with higher energ=
y.
Introns of each LW also require more energy; those introns are much stronger
than those of the crane (much higher speed inside the <span class=3DSpellE>=
eter</span>-flow)
and added energy is proportionally higher. It would accelerate the LW (upwa=
rds)
but it is built in the crane and it must transfer its energy. In other word=
s,
the LW absorbs more energy transferring it to the crane that, at its time,
increases energy of leaving gravitons. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>If the IC moves down, the qu=
estion
is: what happens to the potential energy of the whole IC? In the LW when a =
part
of its mass crosses the moving eteron flow, that mass is accelerated upward=
s. Although
it does not move vertically with regard to the hull, it gets an important
vertical speed inside the flow. Gravitons cross it upwards, leaving it
shortened. In other words, gravitons remove much energy from the mass. The =
EP
must supply such energy. If the whole hull does not move vertically, the
lifting force is high and the energy input is low. If the hull moves upwards
the EP must supply the whole potential energy. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Now, decreasing the energy i=
nput
by the EP, the lifting force becomes less than the hull&#8217;s weight, so =
the
hull begins to accelerate downwards. If the hull falls it absorbs potential
energy (as every falling mass) removing that energy from gravitons. After a
given time, the hull has a falling speed and, as a consequence, a kinetic e=
nergy.
For not crashing against the ground, <span class=3DSpellE>LWs</span> must s=
top it
generating more force than that enough to sustain it still. If <span
class=3DSpellE>LWs</span> work with increased energy, they emit more energy=
 by
leaving gravitons. This additional energy must equal to the mentioned kinet=
ic energy
and the hull stops falling. The whole falling-kinetic-energy is sent to deep
space by the <span class=3DSpellE>LWs</span> as gravitons of increased ener=
gy. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span><span class=3DSpellE>LWs</sp=
an>
behave just like the engine of a helicopter: to move it up, it is necessary
more power; to stop falling speed it is also necessary more power. In both
cases we must input energy. The big advantage of an IC against a helicopter=
 is
the next: a helicopter of a given weight needs 1000 HP to stay still in the
air. An IC of the same weight needs ten to hundred times less energy. Of
course, lifting a payload, additional energy is the same in both cases.
Moreover, an IC has no propeller, so it generates no wind below; it is sile=
nt;
it can lift much heavier weights than a helicopter of similar size.<span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span><o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Jumbo and airbus can be repl=
aced
by crafts with LW. They can be built much more massive and resistant. Paylo=
ads
can be also much heavier. They also use much less energy to &#8220;float&#8=
221;
in air. Of course, for horizontal speeds air&#8217;s resistance is the same
problem. <o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>An important application is =
for
spacecrafts. The LW can be used preferentially to counteract gravity. A cra=
ft
with only NID propulsion has the problem of accumulating falling speed (as =
seen
before). The LW works like legs loaned on the ground. Using it alone to pro=
pel
a craft out of the atmosphere, we must face the problem of inputting potent=
ial
energy. Combining LW and NID, we only need to lift the craft a few meters a=
nd
then to use NID. Remembering the g-turbine, an <span class=3DSpellE>eter</s=
pan>
flow can eliminate potential energy. Moving <span class=3DSpellE>eter</span>
below LW and the craft, both move without inertia. Potential energy is due =
to
gravitons that leave the object upwards with more energy because such objec=
t is
moving upwards. Inside the NID <span class=3DSpellE>eter</span> flow, the c=
raft
is not moving upwards with regard to the <span class=3DSpellE>eter</span>. =
Then
gravitons do not remove energy from the craft and as a consequence potential
energy is switched off. On the other hand, without LW gravitons release ene=
rgy
and accelerate the craft downwards: the free falling. The LW avoids the
dangerous free falling effect and NID avoids the input of a lot of energy to
lift the craft out of the atmosphere.<o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>Then a craft with LW and NID=
 can
move at high speeds (it only needs energy to counteract atmospheric frictio=
n);
it can stop as hanging in the air, it can soar and land slowly and safely.<=
o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span lang=3DEN-US
style=3D'font-size:14.0pt;mso-ansi-language:EN-US'><span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span>In a spacecraft (in every mo=
ving
craft) an energy source is needed. An airbus with LW units needs energy: a
small amount for &#8220;levitating&#8221; and an important amount to move
horizontally due to air&#8217;s resistance. A spacecraft needs energy. Soar=
ing
with LW system and NID, for a craft of 1000 ton 1000 KW is enough. Not too
much. Using electro-chemical cells fed with hydrogen and oxygen as
&#8220;electric fuel&#8221; the fuel-container&#8217;s size is quite
reasonable. Sitting an intron turbine in the craft it works for interplanet=
ary
trips. Recovering hydrogen and oxygen by electrolysis, the turbine supplies
electric power. Such turbine decelerates the craft: it diminishes its absol=
ute
speed in space. That speed is in the order of 220 km/sec. It is equivalent =
to
the heating of the whole craft to 4 million C degrees. Losing a few km/sec,=
 it
is quite enough for every interplanetary trip. Lost speed is easy to recover
approaching a planet in the appropriate direction and letting to its gravit=
y to
accelerate the craft with NID compensation.<span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </spa=
n><o:p></o:p></span></p>

<p class=3DMsoNormal><span lang=3DEN-US style=3D'font-size:14.0pt;mso-ansi-=
language:
EN-US'><o:p>&nbsp;</o:p></span></p>

</div>

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