GEOKINETIC ENERGY

GEOKIN= ETIC ENERGY

<= o:p>

The word GEO-KINETIC represents the kinetic energy of the Earth in relation to the centre of the galaxy. This energy is extremely high if we consider planet E= arth moves at a speed of about 220 km/sec in its galactic orbit. See Diagram 13.= 1

DIAGRAM 13.1 = &nb= sp; = &nb= sp; DIAGRAM 13.2

We would c= all this movement around the centre of the galaxy the Galactic Orbital Velocity (GOV). At all places on the Earth's surface, the GOV vector will have a cer= tain direction and modulus, according to latitude, longitude, date and time.

If we take= an object (within the Earth's point of reference) that moves on a circumferenc= e we can analyse the variation of kinetic energy according to its speed componen= t. If such a variation occurs along a perpendicular plane to the GOV, the added kinetic energy will be at a minimum and will respond to the formula

E = =3D 1/2.m.v², where m is the mass of the object, v is its speed with regar= d to the planet and E is it's added kinetic energy. (See Diagram 13.2 upper side= .)

However if= the speed has non zero component on the GOV vector, there will be a factor that multiplies it. If the angle b= etween the GOV and the speed is f, the variation will be

E =3D 1+cosf.2= 20000 in kg-m-sec units.

If we equa= te V to the GOV, the total kinetic energy of each object on the Earth is given b= y E =3D 1/2.m.V² whose derivative is mV. The energy variation for an objec= t when varying V will be dE =3D mV.dV.= This way, if we accelerate an obje= ct with non-zero component in the direction of the GOV, that component implies proportional energy variations to V, while the perpendicular energy compone= nts to the GOV will vary in proportion to v (v =3D the velocity with regard to = the planet in a perpendicular direction to the GOV).

This means= that, when spinning a wheel, the energy that varies can be represented with a lin= eal abscissa (co-ordinate measured horizontally) and an ordinate (co-ordinate measured vertically) that describes a sinusoid of a very high value. In another way a very high-energy = value with regard to the kinetic energy managed within the environment - values in the order of about 220000 in the direction of the GOV - we are using a kg-m-sec system.

It seems s= trange that, when spinning a wheel, each 90-degree turn can imply a different ener= gy variation. =

However, i= f we move an object perpendicular to the GOV, the forces of acceleration applied= on the object are the same as if we moved this same object parallel to the GOV.

The forces applied here have a support point that moves, and in this case it's the pla= net Earth with the GOV. The force applied to the support point multiplied by the distance that the support po= int travelled provides the energy. The parallel component of the speed vector of Earth "V" is added to the object and determines the energy involv= ed in its movement. <= /span>

Let N repr= esent the force associated with the normal or perpendicular component of the GOV.= Let P represent the parallel component with the GOV.

All forces= can be expressed as a sum of components N and P. With respect to the two import= ant points of reference an object moving at 1 m/sec on the Earth would have the following components:

1. That of= N, in this case it would be 1 m/sec.

2. That of= P - with regard to the Earth the object moves at only 1 m/sec. However with reg= ard to external space it moves at a colossal 220 km/sec.

So the rat= io is very high. To vary the N component would demand little energy however to va= ry the P component demands by nature an enormous amount of energy.<= /span>

If we now = expand this concept such that all moving objects on the face of planet Earth also possess this characteristic, we reach the conclusion that there are two independent systems in quadrature - system N of low energy and also system = P of very high energy. =

Each system interacts only with itself. Each component of speed of one of the systems w= ill have action-reaction effects only with its own system. In this way, when accelerating in the P component, the energy is adjusted with regard to other speeds of the P component never from the N component and vice versa.

Here I sho= uld clarify an important concept. The speed of the Earth, its GOV, is a real speed. It was measured using = the Doppler effect in relation to the surrounding star systems. Therefore, all objects on the surf= ace of the Earth also have an excess of kinetic mass.

The galaxy= may have a general speed in relation to the conducting medium. How would you measure it? You would do so with an eteronic speedometer. Suppose an intron-turbine (discussed in the next chapter however a device that revolves due to vector rotation) was constructed inside a spacecraft. If the spacecraft were to be still within the eteronic medium then the turbine would not work. It doesn't work because there is no intron velocity vector to rotate. If the craft begins to accelerate (with inertial speed), the turbine also begins to release energy. If the turbine is made especially for this purpose, the released energy must be a function of the absolute speed (in relation to the eterons). It will be a formula like E =3D k.v² where E is the measured energy, k is a constant and v is the spee= d.

The second= step is to measure the direction. With a simple EM, we have to find a direction = (of the polar sheaves of the vector-rotator device) where even an intense polar-sheaf-field has null effect. Then, the sheaves are parallel to the sp= eed vector. The last thing to determine is the sense of movement of the polar sheaves. This could be determined the deviation in perpendicular direction = to the movement.

Returning = to our discussion of forces, if we vary the N speed component, the variation of kinetic mass is minor and relatively insignificant in relation to the P component. If on the other ha= nd we vary the speed component of P, the variation of mass is much larger.

Certainly = it's not possible by mechanical means to transfer from components P to N. If we travel at high speed inside a motorcar, we cannot "brake" the vehicle to remove energy from wit= hin. The wheels are in contact with the pavement. It is only through the wheels that= we can remove energy.

If we conn= ect a wheel with an electric alternator, it will brake to the vehicle and give us electric power. The origin of= this kinetic energy is of course the moving vehicle.

In the same way,= if Earth advances through and with regard to space (my apologies here for those fans of the Theory of Relativity) then we might be able to "grasp" space - eteronic space - with "some type of wheel" that might spi= n an alternate.

The idea or method is based on the principle that there is an absolute speed with regar= d to the conductive medium of light and gravity. It is this medium that generates t= he inertia. Intrinsic inertia of= mass DOES NOT EXIST. Inertia is a phenomenon generated solely due to introns. It is the matter wave of an object= in movement. <= /p>

As it is a= wave, and waves tend to move in a straight line in space, inertia impels objects = with speed to follow straight trajectories.&nbs= p; The intron uses the same conductive medium as that of light and in t= he same way, its speed is that of light - d/t.

In areas w= here space is denser, the eterons are of smaller diameter (d). This reduces the speed of light and generates refraction - a denser medium or a densifying of space (the eteron= ic medium). As mentioned in the previous chapter it is possible to refract an intron.

In The Experiment, that medium had been ionized generating sub-electric currents a= nd causing the eterons to in effect (split on one side and reconstituted on the other side) be transported from one place to another.

Creating a gradient based on density and normal to the movement vector of an object, t= he introns will and must be refracted towards the densest area. This is what happened with the EM = (see THE EXPERIMENT). This was pos= sible because the intron doesn't move in the same way as the photon. Instead the reader will remember t= hat the intron has the same structure as the graviton. A free graviton as well = as the photon travels at the speed of light. The intron is a "caught graviton" (caught by the particle); its formation is at the speed of l= ight (two half waves - one ahead and one behind and backwards of the particle), but it DOES NOT travel a wavelength = by cycle (like the photon): its average speed is that of the particle. This is= the sole difference between an intron and a graviton. In other words, the press= ure of the particle on the medium creates the intron; the graviton is similar, = but instead of a particle, the pressure is generated at the centre of the same graviton. The photon travels by transferring strong dipoles and pressure perpendicular to its polar sheaves.

A particle= can detect a difference on density by the existence of just one other particle = and even with the violent interaction that takes place there was a necessary ch= ange in density

The creati= on of a denser spatial volume caused by the existence of a sub-electric current as described in the chapter THE EXPERIMENT would by necessity generate a minim= um refraction of a photon. Howev= er the photon travels through the area at the speed of light. When an object moves at much lower= speed it is a "prisoner" to its intron that flashes within the centre of the particle that generates it.

In other w= ords, the intron dies and becomes reborn within each cycle, remembering the last direction-vector. In each cyc= le, the refraction is of a very small angle, however as the frequency of the in= tron is extremely high, the deviations of each cycle add together with a result = that is significant in terms of an important practical value within relatively l= ow densities.

The deviat= ion of the EM is a variation of the speed-vector of an object. It doesn't vary the modulus (veloc= ity vector), but it does vary the direction.&n= bsp; For that reason, this variation requires no energy at least theoreti= cally.

With regar= d to modulus the meaning of which can be described using the following example.<= span style=3D'mso-spacerun:yes'> Consider a force vector. It has:

1. A direction and

2. A modulus.

The direct= ion is given by (in 3 dimensions) an xyz component in some unit eg cm, inch or km = etc. The modulus is the sole force would be given units in kg, pounds or tons et= c. Mathematically, the modulus is the square root of the sum of squares of the elements (xyz) and is also named the Absolute Value. In our case we have been using the= term - velocity vector. The components x y z, are components on a coordinate-axe= s. The square root of the sum of squares is then the modulus.

Modulus =3D (x² + y² + z²)^1/2

component (v1), and a diminishing P component (pro= jection of V1 on GOV). (See Diagram 13.2, lower side)

A sm= all rotation of, say one thousandth, generates an N component v1 of about 220 m= /sec with regard to the planet Earth. Stated in another way it generates a speed with regard to Earth, wit= hout demanding any energy, since it doesn't vary the modulus. The deviated object will want to move on different orbit to the GOV and its this difference that generates a different speed with regard to the planet.

In describ= ing a "Rotation" of a vector I mean only that the MODULUS does not vary. Translated, the absolute speed does not vary, however the direction does. Operation of the EM causes a gradient in eteronic compression and a subsequ= ent rotation in direction towards the denser part of the gradient as long as the gradient is perpendicular to the GOV. This rotation has no bearing on the modulus and so no energy is requ= ired for the observed display of movement. Rotating the direction, the EM changes its own GOV and it will move = in a different direction with regard to Earth.

This way, = any bond between the object and the planet will tend to de-accelerate the plane= t, removing energy from it and braking it.&nb= sp;

For that r= eason I have called it Geokinetic Energy.

Practicall= y, the deviation of components will appear on a perpendicular plane to the GOV. The forces will be those caused by= Earth when trying to return the object to its original galactic orbit. This way, it takes energy from the= P component and in effect gives it to the N component. In short a colossal FREE ENERGY so= urce.

We have considered as GOV the tangential speed of the solar system around the galaxy’s center. We ignore the galaxy’s speed with regard to the conducting medium. However, the vectorial sum of that speed and the GOV wil= l be the Absolute Space Velocity (= ASV).